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WebJun 21, 2016 · 4 Follow 0. Ishwarmani, Meritnation Expert added an answer, on 21/6/16. Dear Student, Please find below the solution to the asked query: cot 70 ° - tan 90 ° - 70 ° = cot 70 ° - cot 20 ° = cos 70 ° sin 70 ° - cos 20 ° sin 20 ° = cos 70 ° sin 70 ° - cos 20 ° sin 20 ° = cos 70 ° sin 20 ° - cos 20 ° sin 70 ° sin 70 ° sin 20 ° = 2 ... WebNCERT Solutions For Class 9. NCERT Solutions For Class 9 Social Science; NCERT Solutions For Class 9 Maths. NCERT Solutions For Class 9 Maths Chapter 1 scott hussey photography
The value of cot 54°/tan 36°+tan 20°/cot 70° is - BYJU
Web7 years ago. = cot70 + 4cos70. = cos70 / sin70 + 4cos70. = cos70 ( 1 / sin70 + 4) = sin20 ( 1 / sin70 + 4) After this step use the sin table and then substitube the values of sin20 and sin70. Actually I dont know how to use the sin table so i copied the values of sin20 and sin 70 from the calculator. = 0.34 ( 1 / 0.93 + 4) Webcot54°tan36° + tan20°cot70°= cot90° - 36°tan36° + tan20°cot90° - 20°= tan36°tan36° + tan20°tan20°= 1 + 1 = 2 Previous Year Papers. Download Solved Question Papers Free for Offline Practice and view Solutions Online. Test Series. Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly. WebNov 30, 2016 · (1 + sec 20° + cot 70°) (1 - cosec 20° + tan70°) ⇒ (1 + sec 20° + tan 20°) (1 - cosec 20° + cot20°) ⇒ ( 1 + 1 c o s 20 + s i n 20 c o s 20) ( 1 − 1 s i n 20 + c o s 20 s i n 20) ⇒ ( c o s 20 + 1 + s i n 20 c o s 20) ( s i n 20 − 1 + c o s 20 s i n 20) ⇒ ( s i n 20 ∘ + c o s 20 ∘ + 1) ( s i n 20 ∘ + c o s 20 ∘ − 1) s i n 20 ∘ c o s 20 ∘ preppy sweatpants