Web3 apr. 2024 · But the requirement to melt 10 g of ice would be 800 c a l , So at best the water would melt some of the ice and the mixture would remain at 0 ∘ C . Hence we can say from the above observation that the final temperature will be 0 ∘ C That is Option (C). Note Specific heat is equal to the energy needed to vary a unit mass of fabric by 1 ∘ C . WebAmount of heat energy gained by 10 g of water (obtained from ice) at 0 o C to raise its temperature to T o C = 10 × 4.2 × (T-0)=42T Amount of heat energy released by 10 g of water at 10 o C to lower its temperature to T o C = 10 × 4.2 × (10-T) = 420-42T Heat energy gained = Heat energy lost 210 + 3360 + 42T = 420-42T T = -37.5 o C
10g of ice at 0℃ absorbs 5460 J of heat energy to melt and …
Web29 dec. 2024 · 10 gm of ice cubes at 0°C are released in a tumbler (water equivalent 55 g) at 40°C. Assuming that negligible heat is taken from the surroundings, the temperature of water in the tumbler becomes nearely (L = 80 cal/g) (a) 31°C (b) 22°C (c) 19 °C (d) 15 °C properties of matter neet 1 Answer +1 vote answered Dec 29, 2024 by aditi (76.2k points) Web3 apr. 2024 · But the requirement to melt 10 g of ice would be 800 c a l , So at best the water would melt some of the ice and the mixture would remain at 0 ∘ C . Hence we can … doodlelearning reviews
15 g ice at `0^C` is mixed with 10 g water at `40^C`. Find the ...
WebAnswer (1 of 2): It requires 800cal to melt 10 g of ice giving 10g of water at 0C those800cal came from 100g of water at 50C lowering its temperature 8degrees to 42C So we have 10g at 0C and 100g at 42C 10x =100[42-x]; x = 420 - 10x; 11x=420; x=~38.2C WebQuestion From – DC Pandey PHYSICS Class 11 Chapter 22 Question – 006 CALORIMETRY & HEAT TRANSFER CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-15 g ice at `0... Web17 aug. 2024 · The temperature of 170g of water at 50degree celsius is lowered to 5degree celcius by adding certain amount of ice to it.Find the mass of ice added . (Take ,specific … doodle learning parent dashboard